Whakaoti i te {l}{1/2{(x-2/3)}=0}{y=2*1/{(frac{1*{(2)}+1}{2})}}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { \frac{1}{2} {(x - \frac{2}{3})} = 0 }\\ { y = 2 \cdot 1 / {(\frac{1 \cdot {(2)} + 1}{2})} }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c

$$c = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Me whakarea ngā taha e rua ki te 2, te tau utu o \frac{1}{2}. Ko te tau i whakarea ki te kore ka hua ko te kore.

$$x-\frac{2}{3}=0$$

Me tāpiri te \frac{2}{3} ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$x=\frac{2}{3}$$

Whakaarohia te whārite tuarua. Whakareatia te 2 ki te 1, ka 2.

$$y=\frac{2}{\frac{1\times 2+1}{2}}$$

Whakareatia te 1 ki te 2, ka 2.

$$y=\frac{2}{\frac{2+1}{2}}$$

Tāpirihia te 2 ki te 1, ka 3.

$$y=\frac{2}{\frac{3}{2}}$$

Whakawehe 2 ki te \frac{3}{2} mā te whakarea 2 ki te tau huripoki o \frac{3}{2}.

$$y=2\times \frac{2}{3}$$

Whakareatia te 2 ki te \frac{2}{3}, ka \frac{4}{3}.

$$y=\frac{4}{3}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=\frac{4}{3}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\frac{4}{3}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=\frac{4}{3}$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=\frac{4}{3}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{2}{3} y=\frac{4}{3} z=\frac{4}{3} a=\frac{4}{3} b=\frac{4}{3} c=\frac{4}{3}$$