Whakaoti i te {l}{1*5x+1/2-0*2x/6=1}{y=2}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { \frac{1 \cdot 5 x + 1}{2} - \frac{0 \cdot 2 x}{6} = 1 }\\ { y = 2 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c, d

$$d=2$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 2,6.

$$3\left(1\times 5x+1\right)+0\times 2x=6$$

Whakareatia te 1 ki te 5, ka 5.

$$3\left(5x+1\right)+0\times 2x=6$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 5x+1.

$$15x+3+0\times 2x=6$$

Whakareatia te 0 ki te 2, ka 0.

$$15x+3+0x=6$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$15x+3+0=6$$

Tāpirihia te 3 ki te 0, ka 3.

$$15x+3=6$$

Tangohia te 3 mai i ngā taha e rua.

$$15x=6-3$$

Tangohia te 3 i te 6, ka 3.

$$15x=3$$

Whakawehea ngā taha e rua ki te 15.

$$x=\frac{3}{15}$$

Whakahekea te hautanga \frac{3}{15} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$x=\frac{1}{5}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{1}{5} y=2 z=2 a=2 b=2 c=2 d=2$$