Whakaoti i te {l}{0.5/0.15=n/1.2}{o=n}{p=o}{q=p}{r=q}{s=r}{text{Solvefor}ttext{where}}{t=s}

$$\left. \begin{array} { l } { \frac{0.5}{0.15} = \frac{n}{1.2} }\\ { o = n }\\ { p = o }\\ { q = p }\\ { r = q }\\ { s = r }\\ { \text{Solve for } t \text{ where} } \\ { t = s } \end{array} \right.$$

Whakaoti mō n, o, p, q, r, s, t

$$t=4$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakarohaina te \frac{0.5}{0.15} mā te whakarea i te taurunga me te tauraro ki te 100.

$$\frac{50}{15}=\frac{n}{1.2}$$

Whakahekea te hautanga \frac{50}{15} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 5.

$$\frac{10}{3}=\frac{n}{1.2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\frac{n}{1.2}=\frac{10}{3}$$

Me whakarea ngā taha e rua ki te 1.2.

$$n=\frac{10}{3}\times 1.2$$

Whakareatia te \frac{10}{3} ki te 1.2, ka 4.

$$n=4$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$o=4$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$p=4$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$q=4$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$r=4$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$s=4$$

Whakaarohia te whārite (7). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$t=4$$

Kua oti te pūnaha te whakatau.

$$n=4 o=4 p=4 q=4 r=4 s=4 t=4$$