Whakaoti i te left(173-47.73+0.1p^1.2+1750+7825/pright)P=0

$$\left( 173-47.73+0.1 { p }^{ 1.2 } + \frac{ 1750+7825 }{ p } \right) P = 0$$

Whakaoti mō P (complex solution)

$$\left\{\begin{matrix}\\P=0\text{, }&\text{unconditionally}\\P\in \mathrm{C}\text{, }&10p^{2.2}+12527p+957500=0\text{ and }p\neq 0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te p.

$$\left(173-47.73+0.1p^{1.2}+\frac{1750+7825}{p}\right)Pp=0$$

Tangohia te 47.73 i te 173, ka 125.27.

$$\left(125.27+0.1p^{1.2}+\frac{1750+7825}{p}\right)Pp=0$$

Tāpirihia te 1750 ki te 7825, ka 9575.

$$\left(125.27+0.1p^{1.2}+\frac{9575}{p}\right)Pp=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te 125.27+0.1p^{1.2}+\frac{9575}{p} ki te P.

$$\left(125.27P+0.1p^{1.2}P+\frac{9575}{p}P\right)p=0$$

Tuhia te \frac{9575}{p}P hei hautanga kotahi.

$$\left(125.27P+0.1p^{1.2}P+\frac{9575P}{p}\right)p=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te 125.27P+0.1p^{1.2}P+\frac{9575P}{p} ki te p.

$$125.27Pp+0.1p^{1.2}Pp+\frac{9575P}{p}p=0$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 1.2 me te 1 kia riro ai te 2.2.

$$125.27Pp+0.1p^{2.2}P+\frac{9575P}{p}p=0$$

Tuhia te \frac{9575P}{p}p hei hautanga kotahi.

$$125.27Pp+0.1p^{2.2}P+\frac{9575Pp}{p}=0$$

Me whakakore tahi te p i te taurunga me te tauraro.

$$125.27Pp+0.1p^{2.2}P+9575P=0$$

Pahekotia ngā kīanga tau katoa e whai ana i te P.

$$\left(125.27p+0.1p^{2.2}+9575\right)P=0$$

He hanga arowhānui tō te whārite.

$$\left(\frac{p^{2.2}}{10}+\frac{12527p}{100}+9575\right)P=0$$

Whakawehe 0 ki te 125.27p+0.1p^{2.2}+9575.

$$P=0$$

Whakaoti mō P

$$\left\{\begin{matrix}\\P=0\text{, }&\text{unconditionally}\\P\in \mathrm{R}\text{, }&10p^{2.2}+12527p+957500=0\text{ and }p\neq 0\end{matrix}\right.$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te p.

$$\left(173-47.73+0.1p^{1.2}+\frac{1750+7825}{p}\right)Pp=0$$

Tangohia te 47.73 i te 173, ka 125.27.

$$\left(125.27+0.1p^{1.2}+\frac{1750+7825}{p}\right)Pp=0$$

Tāpirihia te 1750 ki te 7825, ka 9575.

$$\left(125.27+0.1p^{1.2}+\frac{9575}{p}\right)Pp=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te 125.27+0.1p^{1.2}+\frac{9575}{p} ki te P.

$$\left(125.27P+0.1p^{1.2}P+\frac{9575}{p}P\right)p=0$$

Tuhia te \frac{9575}{p}P hei hautanga kotahi.

$$\left(125.27P+0.1p^{1.2}P+\frac{9575P}{p}\right)p=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te 125.27P+0.1p^{1.2}P+\frac{9575P}{p} ki te p.

$$125.27Pp+0.1p^{1.2}Pp+\frac{9575P}{p}p=0$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 1.2 me te 1 kia riro ai te 2.2.

$$125.27Pp+0.1p^{2.2}P+\frac{9575P}{p}p=0$$

Tuhia te \frac{9575P}{p}p hei hautanga kotahi.

$$125.27Pp+0.1p^{2.2}P+\frac{9575Pp}{p}=0$$

Me whakakore tahi te p i te taurunga me te tauraro.

$$125.27Pp+0.1p^{2.2}P+9575P=0$$

Pahekotia ngā kīanga tau katoa e whai ana i te P.

$$\left(125.27p+0.1p^{2.2}+9575\right)P=0$$

He hanga arowhānui tō te whārite.

$$\left(\frac{p^{2.2}}{10}+\frac{12527p}{100}+9575\right)P=0$$

Whakawehe 0 ki te 125.27p+0.1p^{2.2}+9575.

$$P=0$$