Whakaoti i te left(-2+8iright)divleft(-2+6iright)

$$\left( -2+8i \right) \div \left( -2+6i \right)$$

Aromātai

$$\frac{13}{10}-\frac{1}{10}i=1.3-0.1i$$

Ngā Upane Otinga

Whakareatia te taurunga me te tauraro ki te haumi hiato o te tauraro, -2-6i.

$$\frac{\left(-2+8i\right)\left(-2-6i\right)}{\left(-2+6i\right)\left(-2-6i\right)}$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(-2+8i\right)\left(-2-6i\right)}{\left(-2\right)^{2}-6^{2}i^{2}}$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$\frac{\left(-2+8i\right)\left(-2-6i\right)}{40}$$

Me whakarea ngā tau matatini -2+8i me -2-6i pēnā i te whakarea huarua.

$$\frac{-2\left(-2\right)-2\times \left(-6i\right)+8i\left(-2\right)+8\left(-6\right)i^{2}}{40}$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$\frac{-2\left(-2\right)-2\times \left(-6i\right)+8i\left(-2\right)+8\left(-6\right)\left(-1\right)}{40}$$

Mahia ngā whakarea i roto o -2\left(-2\right)-2\times \left(-6i\right)+8i\left(-2\right)+8\left(-6\right)\left(-1\right).

$$\frac{4+12i-16i+48}{40}$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 4+12i-16i+48.

$$\frac{4+48+\left(12-16\right)i}{40}$$

Mahia ngā tāpiri i roto o 4+48+\left(12-16\right)i.

$$\frac{52-4i}{40}$$

Whakawehea te 52-4i ki te 40, kia riro ko \frac{13}{10}-\frac{1}{10}i.

$$\frac{13}{10}-\frac{1}{10}i$$

Wāhi Tūturu

$$\frac{13}{10} = 1\frac{3}{10} = 1.3$$

Ngā Upane Otinga

Me whakarea te taurunga me te tauraro o \frac{-2+8i}{-2+6i} ki te haumi hiato o te tauraro, -2-6i.

$$Re(\frac{\left(-2+8i\right)\left(-2-6i\right)}{\left(-2+6i\right)\left(-2-6i\right)})$$

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$Re(\frac{\left(-2+8i\right)\left(-2-6i\right)}{\left(-2\right)^{2}-6^{2}i^{2}})$$

Hei tōna tikanga, ko te i^{2} ko -1. Tātaitia te tauraro.

$$Re(\frac{\left(-2+8i\right)\left(-2-6i\right)}{40})$$

Me whakarea ngā tau matatini -2+8i me -2-6i pēnā i te whakarea huarua.

$$Re(\frac{-2\left(-2\right)-2\times \left(-6i\right)+8i\left(-2\right)+8\left(-6\right)i^{2}}{40})$$

Hei tōna tikanga, ko te i^{2} ko -1.

$$Re(\frac{-2\left(-2\right)-2\times \left(-6i\right)+8i\left(-2\right)+8\left(-6\right)\left(-1\right)}{40})$$

Mahia ngā whakarea i roto o -2\left(-2\right)-2\times \left(-6i\right)+8i\left(-2\right)+8\left(-6\right)\left(-1\right).

$$Re(\frac{4+12i-16i+48}{40})$$

Whakakotahitia ngā wāhi tūturu me ngā wāhi pōhewa ki 4+12i-16i+48.

$$Re(\frac{4+48+\left(12-16\right)i}{40})$$

Mahia ngā tāpiri i roto o 4+48+\left(12-16\right)i.

$$Re(\frac{52-4i}{40})$$

Whakawehea te 52-4i ki te 40, kia riro ko \frac{13}{10}-\frac{1}{10}i.

$$Re(\frac{13}{10}-\frac{1}{10}i)$$

Ko te wāhi tūturu o \frac{13}{10}-\frac{1}{10}i ko \frac{13}{10}.

$$\frac{13}{10}$$