\left\{ \begin{array}{l}{ 5 x + 3 y = c }\\{ ( 3 k + 20 ) x = 4 c + 3 }\end{array} \right.
Whakaoti mō x, y (complex solution)
\left\{\begin{matrix}x=\frac{4c+3}{3k+20}\text{, }y=-\frac{5-ck}{3k+20}\text{, }&k\neq -\frac{20}{3}\\x=\frac{3\left(-4y-1\right)}{20}\text{, }y\in \mathrm{C}\text{, }&c=-\frac{3}{4}\text{ and }k=-\frac{20}{3}\end{matrix}\right.
Whakaoti mō x, y
\left\{\begin{matrix}x=\frac{4c+3}{3k+20}\text{, }y=-\frac{5-ck}{3k+20}\text{, }&k\neq -\frac{20}{3}\\x=\frac{3\left(-4y-1\right)}{20}\text{, }y\in \mathrm{R}\text{, }&c=-\frac{3}{4}\text{ and }k=-\frac{20}{3}\end{matrix}\right.
Graph
Tohaina
Kua tāruatia ki te papatopenga
\left(3k+20\right)x=4c+3,5x+3y=c
Hei whakaoti i ētahi whārite takirua mā te whakakapinga, me whakaoti tētahi whārite i te tuatahi mō tētahi o ngā taurangi. Ka whakakapi i te otinga mō taua taurangi ki tērā o ngā whārite.
\left(3k+20\right)x=4c+3
Tīpakohia tētahi o ngā whārite e rua he māmā ake ki te whakaoti mō te x mā te wehe i te x i te taha mauī o te tohu ōrite.
x=\frac{4c+3}{3k+20}
Whakawehea ngā taha e rua ki te 3k+20.
5\times \frac{4c+3}{3k+20}+3y=c
Whakakapia te \frac{4c+3}{3k+20} mō te x ki tērā atu whārite, 5x+3y=c.
\frac{5\left(4c+3\right)}{3k+20}+3y=c
Whakareatia 5 ki te \frac{4c+3}{3k+20}.
3y=\frac{3\left(ck-5\right)}{3k+20}
Me tango \frac{5\left(4c+3\right)}{3k+20} mai i ngā taha e rua o te whārite.
y=\frac{ck-5}{3k+20}
Whakawehea ngā taha e rua ki te 3.
x=\frac{4c+3}{3k+20},y=\frac{ck-5}{3k+20}
Kua oti te pūnaha te whakatau.
\left(3k+20\right)x=4c+3,5x+3y=c
Hei whakaoti i ētahi whārite takirua mā te whakakapinga, me whakaoti tētahi whārite i te tuatahi mō tētahi o ngā taurangi. Ka whakakapi i te otinga mō taua taurangi ki tērā o ngā whārite.
\left(3k+20\right)x=4c+3
Tīpakohia tētahi o ngā whārite e rua he māmā ake ki te whakaoti mō te x mā te wehe i te x i te taha mauī o te tohu ōrite.
x=\frac{4c+3}{3k+20}
Whakawehea ngā taha e rua ki te 3k+20.
5\times \frac{4c+3}{3k+20}+3y=c
Whakakapia te \frac{4c+3}{3k+20} mō te x ki tērā atu whārite, 5x+3y=c.
\frac{5\left(4c+3\right)}{3k+20}+3y=c
Whakareatia 5 ki te \frac{4c+3}{3k+20}.
3y=\frac{3\left(ck-5\right)}{3k+20}
Me tango \frac{5\left(4c+3\right)}{3k+20} mai i ngā taha e rua o te whārite.
y=\frac{ck-5}{3k+20}
Whakawehea ngā taha e rua ki te 3.
x=\frac{4c+3}{3k+20},y=\frac{ck-5}{3k+20}
Kua oti te pūnaha te whakatau.
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