Whakaoti i te {l}{y+x-xy=0}{9-x+1=0}

$$\left\{ \begin{array} { l } { y + x - x y = 0 } \\ { 9 - x + 1 = 0 } \end{array} \right.$$

Whakaoti mō y, x

$$x=10$$

$$y = \frac{10}{9} = 1\frac{1}{9} \approx 1.111111111$$

Ngā Upane Otinga

Whakaarohia te whārite tuarua. Tāpirihia te 9 ki te 1, ka 10.

$$10-x=0$$

Tangohia te 10 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-x=-10$$

Whakawehea ngā taha e rua ki te -1.

$$x=\frac{-10}{-1}$$

Ka taea te hautanga \frac{-10}{-1} te whakamāmā ki te 10 mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x=10$$

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y+10-10y=0$$

Pahekotia te y me -10y, ka -9y.

$$-9y+10=0$$

Tangohia te 10 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-9y=-10$$

Whakawehea ngā taha e rua ki te -9.

$$y=\frac{-10}{-9}$$

Ka taea te hautanga \frac{-10}{-9} te whakamāmā ki te \frac{10}{9} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$y=\frac{10}{9}$$

Kua oti te pūnaha te whakatau.

$$y=\frac{10}{9} x=10$$