Whakaoti i te {l}{x+y+z=12}{x+2y-z=6}{3x-y+z=10}

$$\left\{ \begin{array} { l } { x + y + z = 12 } \\ { x + 2 y - z = 6 } \\ { 3 x - y + z = 10 } \end{array} \right.$$

Whakaoti mō x, y, z

$$x=3$$

$$y=4$$

$$z=5$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me whakaoti te x+y+z=12 mō x.

$$x=-y-z+12$$

Whakakapia te -y-z+12 mō te x i te whārite tuarua me te tuatoru.

$$-y-z+12+2y-z=6 3\left(-y-z+12\right)-y+z=10$$

Me whakaoti ēnei whārite mō y me z takitahi.

$$y=-6+2z z=13-2y$$

Whakakapia te -6+2z mō te y i te whārite z=13-2y.

$$z=13-2\left(-6+2z\right)$$

Me whakaoti te z=13-2\left(-6+2z\right) mō z.

$$z=5$$

Whakakapia te 5 mō te z i te whārite y=-6+2z.

$$y=-6+2\times 5$$

Tātaitia te y i te y=-6+2\times 5.

$$y=4$$

Whakakapia te 4 mō te y me te 5 mō z i te whārite x=-y-z+12.

$$x=-4-5+12$$

Tātaitia te x i te x=-4-5+12.

$$x=3$$

Kua oti te pūnaha te whakatau.

$$x=3 y=4 z=5$$