Whakaoti i te {l}{ax-y=3}{(a-4)x+sqrt{2}=4}

$$\left\{ \begin{array} { l } { a x - y = 3 } \\ { ( a - 4 ) x + \sqrt { 2 } = 4 } \end{array} \right.$$

Whakaoti mō x, y

$$x=-\frac{\sqrt{2}-4}{a-4}$$

$$y=\frac{-\sqrt{2}a+a+12}{a-4}$$

$$a\neq 4$$

Ngā Upane e Whakamahi ana i te Whakakapinga

Hei whakaoti i ētahi whārite takirua mā te whakakapinga, me whakaoti tētahi whārite i te tuatahi mō tētahi o ngā taurangi. Ka whakakapi i te otinga mō taua taurangi ki tērā o ngā whārite.

$$\left(a-4\right)x+\sqrt{2}=4,ax-y=3$$

Tīpakohia tētahi o ngā whārite e rua he māmā ake ki te whakaoti mō te x mā te wehe i te x i te taha mauī o te tohu ōrite.

$$\left(a-4\right)x+\sqrt{2}=4$$

Me tango \sqrt{2} mai i ngā taha e rua o te whārite.

$$\left(a-4\right)x=4-\sqrt{2}$$

Whakawehea ngā taha e rua ki te a-4.

$$x=\frac{4-\sqrt{2}}{a-4}$$

Whakakapia te \frac{4-\sqrt{2}}{a-4} mō te x ki tērā atu whārite, ax-y=3.

$$a\times \frac{4-\sqrt{2}}{a-4}-y=3$$

Whakareatia a ki te \frac{4-\sqrt{2}}{a-4}.

$$\frac{\left(4-\sqrt{2}\right)a}{a-4}-y=3$$

Me tango \frac{a\left(4-\sqrt{2}\right)}{a-4} mai i ngā taha e rua o te whārite.

$$-y=\frac{\sqrt{2}a-a-12}{a-4}$$

Whakawehea ngā taha e rua ki te -1.

$$y=-\frac{\sqrt{2}a-a-12}{a-4}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{4-\sqrt{2}}{a-4},y=-\frac{\sqrt{2}a-a-12}{a-4}$$