Whakaoti i te {l}{5x-3y=12}{x-2y=1}

$$\left\{ \begin{array} { l } { 5 x - 3 y = 12 } \\ { x - 2 y = 1 } \end{array} \right.$$

Whakaoti mō x, y

$$x=3$$

$$y=1$$

Ngā Upane e Whakamahi ana i te Whakakapinga

Hei whakaoti i ētahi whārite takirua mā te whakakapinga, me whakaoti tētahi whārite i te tuatahi mō tētahi o ngā taurangi. Ka whakakapi i te otinga mō taua taurangi ki tērā o ngā whārite.

$$5x-3y=12,x-2y=1$$

Kōwhiria tētahi o ngā whārite ka whakaotia mō te x mā te wehe i te x i te taha mauī o te tohu ōrite.

$$5x-3y=12$$

Me tāpiri 3y ki ngā taha e rua o te whārite.

$$5x=3y+12$$

Whakawehea ngā taha e rua ki te 5.

$$x=\frac{1}{5}\left(3y+12\right)$$

Whakareatia \frac{1}{5} ki te 12+3y.

$$x=\frac{3}{5}y+\frac{12}{5}$$

Whakakapia te \frac{12+3y}{5} mō te x ki tērā atu whārite, x-2y=1.

$$\frac{3}{5}y+\frac{12}{5}-2y=1$$

Tāpiri \frac{3y}{5} ki te -2y.

$$-\frac{7}{5}y+\frac{12}{5}=1$$

Me tango \frac{12}{5} mai i ngā taha e rua o te whārite.

$$-\frac{7}{5}y=-\frac{7}{5}$$

Whakawehea ngā taha e rua o te whārite ki te -\frac{7}{5}, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$y=1$$

Whakaurua te 1 mō y ki x=\frac{3}{5}y+\frac{12}{5}. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō x hāngai tonu.

$$x=\frac{3+12}{5}$$

Tāpiri \frac{12}{5} ki te \frac{3}{5} mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$x=3$$

Kua oti te pūnaha te whakatau.

$$x=3,y=1$$

Ngā Upane e Whakamahi ana i Ngā Poukapa

Tuhia ngā whārite ki te tānga ngahuru ka whakamahi i ngā poukapa hei whakaoti i te pūnaha o ngā whārite.

$$5x-3y=12,x-2y=1$$

Tuhia ngā whārite ki te tikanga tātai poukapa.

$$\left(\begin{matrix}5&-3\\1&-2\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}12\\1\end{matrix}\right)$$

Whakarea mauī i te whārite ki te poukapa kōaro o \left(\begin{matrix}5&-3\\1&-2\end{matrix}\right).

$$inverse(\left(\begin{matrix}5&-3\\1&-2\end{matrix}\right))\left(\begin{matrix}5&-3\\1&-2\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}5&-3\\1&-2\end{matrix}\right))\left(\begin{matrix}12\\1\end{matrix}\right)$$

Ko te hua o tētahi poukapa me te kōaro ko te poukapa tuakiri.

$$\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}5&-3\\1&-2\end{matrix}\right))\left(\begin{matrix}12\\1\end{matrix}\right)$$

Whakareatia ngā poukapa kei te taha mauī o te tohu ōrite.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}5&-3\\1&-2\end{matrix}\right))\left(\begin{matrix}12\\1\end{matrix}\right)$$

Mō te poukapa 2\times 2 \left(\begin{matrix}a&b\\c&d\end{matrix}\right), ko te \left(\begin{matrix}\frac{d}{ad-bc}&\frac{-b}{ad-bc}\\\frac{-c}{ad-bc}&\frac{a}{ad-bc}\end{matrix}\right) te poukapa kōaro, nō reira ka taea te tuhi anō te whārite poukapa hei rapanga whakarea poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}-\frac{2}{5\left(-2\right)-\left(-3\right)}&-\frac{-3}{5\left(-2\right)-\left(-3\right)}\\-\frac{1}{5\left(-2\right)-\left(-3\right)}&\frac{5}{5\left(-2\right)-\left(-3\right)}\end{matrix}\right)\left(\begin{matrix}12\\1\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{2}{7}&-\frac{3}{7}\\\frac{1}{7}&-\frac{5}{7}\end{matrix}\right)\left(\begin{matrix}12\\1\end{matrix}\right)$$

Whakareatia ngā poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{2}{7}\times 12-\frac{3}{7}\\\frac{1}{7}\times 12-\frac{5}{7}\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}3\\1\end{matrix}\right)$$

Tangohia ngā huānga poukapa x me y.

$$x=3,y=1$$

Ngā Upane e Whakamahi i te Tangohanga

Hei whakaoti mā te tangohanga, ko ngā tau whakarea o tētahi o ngā taurangi me mātua ōrite i ngā whārite e rua kia whakakorehia ai te taurangi ina tangohia tētahi whārite mai i tētahi atu.

$$5x-3y=12,x-2y=1$$

Kia ōrite ai a 5x me x, whakareatia ngā kīanga tau katoa kei ia taha o te whārite tuatahi ki te 1 me ngā kīanga tau katoa kei ia taha o te whārite tuarua ki te 5.

$$5x-3y=12,5x+5\left(-2\right)y=5$$

Whakarūnātia.

$$5x-3y=12,5x-10y=5$$

Me tango 5x-10y=5 mai i 5x-3y=12 mā te tango i ngā kīanga tau ōrite i ia taha o te tohu ōrite.

$$5x-5x-3y+10y=12-5$$

Tāpiri 5x ki te -5x. Ka whakakore atu ngā kupu 5x me -5x, ka toe he whārite me tētahi taurangi kotahi ka taea te whakaoti.

$$-3y+10y=12-5$$

Tāpiri -3y ki te 10y.

$$7y=12-5$$

Tāpiri 12 ki te -5.

$$7y=7$$

Whakawehea ngā taha e rua ki te 7.

$$y=1$$

Whakaurua te 1 mō y ki x-2y=1. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō x hāngai tonu.

$$x-2=1$$

Me tāpiri 2 ki ngā taha e rua o te whārite.

$$x=3$$

Kua oti te pūnaha te whakatau.

$$x=3,y=1$$