Whakaoti i te {l}{4n-2m-3r=1}{m+3n-5r=-4}{3m-5n+r=0}

$$\left\{ \begin{array} { l } { 4 n - 2 m - 3 r = 1 } \\ { m + 3 n - 5 r = - 4 } \\ { 3 m - 5 n + r = 0 } \end{array} \right.$$

Whakaoti mō n, m, r

$$r=-1$$

$$n=-2$$

$$m=-3$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me raupapa anō ngā whārite.

$$m+3n-5r=-4 4n-2m-3r=1 3m-5n+r=0$$

Me whakaoti te m+3n-5r=-4 mō m.

$$m=-3n+5r-4$$

Whakakapia te -3n+5r-4 mō te m i te whārite tuarua me te tuatoru.

$$4n-2\left(-3n+5r-4\right)-3r=1 3\left(-3n+5r-4\right)-5n+r=0$$

Me whakaoti ēnei whārite mō n me r takitahi.

$$n=\frac{13}{10}r-\frac{7}{10} r=\frac{3}{4}+\frac{7}{8}n$$

Whakakapia te \frac{13}{10}r-\frac{7}{10} mō te n i te whārite r=\frac{3}{4}+\frac{7}{8}n.

$$r=\frac{3}{4}+\frac{7}{8}\left(\frac{13}{10}r-\frac{7}{10}\right)$$

Me whakaoti te r=\frac{3}{4}+\frac{7}{8}\left(\frac{13}{10}r-\frac{7}{10}\right) mō r.

$$r=-1$$

Whakakapia te -1 mō te r i te whārite n=\frac{13}{10}r-\frac{7}{10}.

$$n=\frac{13}{10}\left(-1\right)-\frac{7}{10}$$

Tātaitia te n i te n=\frac{13}{10}\left(-1\right)-\frac{7}{10}.

$$n=-2$$

Whakakapia te -2 mō te n me te -1 mō r i te whārite m=-3n+5r-4.

$$m=-3\left(-2\right)+5\left(-1\right)-4$$

Tātaitia te m i te m=-3\left(-2\right)+5\left(-1\right)-4.

$$m=-3$$

Kua oti te pūnaha te whakatau.

$$n=-2 m=-3 r=-1$$