Whakaoti i te {l}{4a+2b+c=4}{4a-2b+c=-2}{4a+b=0,5}

$$\left\{ \begin{array} { l } { 4 a + 2 b + c = 4 } \\ { 4 a - 2 b + c = - 2 } \\ { 4 a + b = 0,5 } \end{array} \right.$$

Whakaoti mō a, b, c

$$a=-0.25$$

$$b=1.5$$

$$c=2$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me whakaoti te 4a+2b+c=4 mō c.

$$c=4-4a-2b$$

Whakakapia te 4-4a-2b mō te c i te whārite 4a-2b+c=-2.

$$4a-2b+4-4a-2b=-2$$

Me whakaoti te whārite tuarua mō b me te whārite tuatoru mō a.

$$b=\frac{3}{2} a=-\frac{1}{4}b+\frac{1}{8}$$

Whakakapia te \frac{3}{2} mō te b i te whārite a=-\frac{1}{4}b+\frac{1}{8}.

$$a=-\frac{1}{4}\times \frac{3}{2}+\frac{1}{8}$$

Tātaitia te a i te a=-\frac{1}{4}\times \frac{3}{2}+\frac{1}{8}.

$$a=-\frac{1}{4}$$

Whakakapia te \frac{3}{2} mō te b me te -\frac{1}{4} mō a i te whārite c=4-4a-2b.

$$c=4-4\left(-\frac{1}{4}\right)-2\times \frac{3}{2}$$

Tātaitia te c i te c=4-4\left(-\frac{1}{4}\right)-2\times \frac{3}{2}.

$$c=2$$

Kua oti te pūnaha te whakatau.

$$a=-\frac{1}{4} b=\frac{3}{2} c=2$$