Whakaoti i te {l}{3x-y=4}{x-y=1}

$$\left\{ \begin{array} { l } { 3 x - y = 4 } \\ { x - y = 1 } \end{array} \right.$$

Whakaoti mō x, y

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

$$y=\frac{1}{2}=0.5$$

Ngā Upane e Whakamahi ana i te Whakakapinga

Hei whakaoti i ētahi whārite takirua mā te whakakapinga, me whakaoti tētahi whārite i te tuatahi mō tētahi o ngā taurangi. Ka whakakapi i te otinga mō taua taurangi ki tērā o ngā whārite.

$$3x-y=4,x-y=1$$

Kōwhiria tētahi o ngā whārite ka whakaotia mō te x mā te wehe i te x i te taha mauī o te tohu ōrite.

$$3x-y=4$$

Me tāpiri y ki ngā taha e rua o te whārite.

$$3x=y+4$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{1}{3}\left(y+4\right)$$

Whakareatia \frac{1}{3} ki te y+4.

$$x=\frac{1}{3}y+\frac{4}{3}$$

Whakakapia te \frac{4+y}{3} mō te x ki tērā atu whārite, x-y=1.

$$\frac{1}{3}y+\frac{4}{3}-y=1$$

Tāpiri \frac{y}{3} ki te -y.

$$-\frac{2}{3}y+\frac{4}{3}=1$$

Me tango \frac{4}{3} mai i ngā taha e rua o te whārite.

$$-\frac{2}{3}y=-\frac{1}{3}$$

Whakawehea ngā taha e rua o te whārite ki te -\frac{2}{3}, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$y=\frac{1}{2}$$

Whakaurua te \frac{1}{2} mō y ki x=\frac{1}{3}y+\frac{4}{3}. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō x hāngai tonu.

$$x=\frac{1}{3}\times \frac{1}{2}+\frac{4}{3}$$

Whakareatia \frac{1}{3} ki te \frac{1}{2} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro, ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$x=\frac{1}{6}+\frac{4}{3}$$

Tāpiri \frac{4}{3} ki te \frac{1}{6} mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$x=\frac{3}{2}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{3}{2},y=\frac{1}{2}$$

Ngā Upane e Whakamahi ana i Ngā Poukapa

Tuhia ngā whārite ki te tānga ngahuru ka whakamahi i ngā poukapa hei whakaoti i te pūnaha o ngā whārite.

$$3x-y=4,x-y=1$$

Tuhia ngā whārite ki te tikanga tātai poukapa.

$$\left(\begin{matrix}3&-1\\1&-1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}4\\1\end{matrix}\right)$$

Whakarea mauī i te whārite ki te poukapa kōaro o \left(\begin{matrix}3&-1\\1&-1\end{matrix}\right).

$$inverse(\left(\begin{matrix}3&-1\\1&-1\end{matrix}\right))\left(\begin{matrix}3&-1\\1&-1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}3&-1\\1&-1\end{matrix}\right))\left(\begin{matrix}4\\1\end{matrix}\right)$$

Ko te hua o tētahi poukapa me te kōaro ko te poukapa tuakiri.

$$\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}3&-1\\1&-1\end{matrix}\right))\left(\begin{matrix}4\\1\end{matrix}\right)$$

Whakareatia ngā poukapa kei te taha mauī o te tohu ōrite.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}3&-1\\1&-1\end{matrix}\right))\left(\begin{matrix}4\\1\end{matrix}\right)$$

Mō te poukapa 2\times 2 \left(\begin{matrix}a&b\\c&d\end{matrix}\right), ko te \left(\begin{matrix}\frac{d}{ad-bc}&\frac{-b}{ad-bc}\\\frac{-c}{ad-bc}&\frac{a}{ad-bc}\end{matrix}\right) te poukapa kōaro, nō reira ka taea te tuhi anō te whārite poukapa hei rapanga whakarea poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}-\frac{1}{3\left(-1\right)-\left(-1\right)}&-\frac{-1}{3\left(-1\right)-\left(-1\right)}\\-\frac{1}{3\left(-1\right)-\left(-1\right)}&\frac{3}{3\left(-1\right)-\left(-1\right)}\end{matrix}\right)\left(\begin{matrix}4\\1\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{1}{2}&-\frac{1}{2}\\\frac{1}{2}&-\frac{3}{2}\end{matrix}\right)\left(\begin{matrix}4\\1\end{matrix}\right)$$

Whakareatia ngā poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{1}{2}\times 4-\frac{1}{2}\\\frac{1}{2}\times 4-\frac{3}{2}\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{3}{2}\\\frac{1}{2}\end{matrix}\right)$$

Tangohia ngā huānga poukapa x me y.

$$x=\frac{3}{2},y=\frac{1}{2}$$

Ngā Upane e Whakamahi i te Tangohanga

Hei whakaoti mā te tangohanga, ko ngā tau whakarea o tētahi o ngā taurangi me mātua ōrite i ngā whārite e rua kia whakakorehia ai te taurangi ina tangohia tētahi whārite mai i tētahi atu.

$$3x-y=4,x-y=1$$

Me tango x-y=1 mai i 3x-y=4 mā te tango i ngā kīanga tau ōrite i ia taha o te tohu ōrite.

$$3x-x-y+y=4-1$$

Tāpiri -y ki te y. Ka whakakore atu ngā kupu -y me y, ka toe he whārite me tētahi taurangi kotahi ka taea te whakaoti.

$$3x-x=4-1$$

Tāpiri 3x ki te -x.

$$2x=4-1$$

Tāpiri 4 ki te -1.

$$2x=3$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{3}{2}$$

Whakaurua te \frac{3}{2} mō x ki x-y=1. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō y hāngai tonu.

$$\frac{3}{2}-y=1$$

Me tango \frac{3}{2} mai i ngā taha e rua o te whārite.

$$-y=-\frac{1}{2}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{3}{2},y=\frac{1}{2}$$