Whakaoti i te {l}{2b-c=1}{4a+c=-4}{2a+c=-4}

$$\left\{ \begin{array} { l } { 2 b - c = 1 } \\ { 4 a + c = - 4 } \\ { 2 a + c = - 4 } \end{array} \right.$$

Whakaoti mō b, c, a

$$b = -\frac{3}{2} = -1\frac{1}{2} = -1.5$$

$$c=-4$$

$$a=0$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me whakaoti te 2b-c=1 mō c.

$$c=2b-1$$

Whakakapia te 2b-1 mō te c i te whārite tuarua me te tuatoru.

$$4a+2b-1=-4 2a+2b-1=-4$$

Me whakaoti ēnei whārite mō b me a takitahi.

$$b=-2a-\frac{3}{2} a=-b-\frac{3}{2}$$

Whakakapia te -2a-\frac{3}{2} mō te b i te whārite a=-b-\frac{3}{2}.

$$a=-\left(-2a-\frac{3}{2}\right)-\frac{3}{2}$$

Me whakaoti te a=-\left(-2a-\frac{3}{2}\right)-\frac{3}{2} mō a.

$$a=0$$

Whakakapia te 0 mō te a i te whārite b=-2a-\frac{3}{2}.

$$b=-2\times 0-\frac{3}{2}$$

Tātaitia te b i te b=-2\times 0-\frac{3}{2}.

$$b=-\frac{3}{2}$$

Whakakapia te -\frac{3}{2} mō te b i te whārite c=2b-1.

$$c=2\left(-\frac{3}{2}\right)-1$$

Tātaitia te c i te c=2\left(-\frac{3}{2}\right)-1.

$$c=-4$$

Kua oti te pūnaha te whakatau.

$$b=-\frac{3}{2} c=-4 a=0$$