Whakaoti i te {l}{2a-b=1}{2b-c=1}{2a+c=1}

$$\left\{ \begin{array} { l } { 2 a - b = 1 } \\ { 2 b - c = 1 } \\ { 2 a + c = 1 } \end{array} \right.$$

Whakaoti mō a, b, c

$$a=\frac{2}{3}\approx 0.666666667$$

$$b=\frac{1}{3}\approx 0.333333333$$

$$c=-\frac{1}{3}\approx -0.333333333$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me whakaoti te 2a-b=1 mō b.

$$b=2a-1$$

Whakakapia te 2a-1 mō te b i te whārite 2b-c=1.

$$2\left(2a-1\right)-c=1$$

Me whakaoti te whārite tuarua mō a me te whārite tuatoru mō c.

$$a=\frac{3}{4}+\frac{1}{4}c c=-2a+1$$

Whakakapia te \frac{3}{4}+\frac{1}{4}c mō te a i te whārite c=-2a+1.

$$c=-2\left(\frac{3}{4}+\frac{1}{4}c\right)+1$$

Me whakaoti te c=-2\left(\frac{3}{4}+\frac{1}{4}c\right)+1 mō c.

$$c=-\frac{1}{3}$$

Whakakapia te -\frac{1}{3} mō te c i te whārite a=\frac{3}{4}+\frac{1}{4}c.

$$a=\frac{3}{4}+\frac{1}{4}\left(-\frac{1}{3}\right)$$

Tātaitia te a i te a=\frac{3}{4}+\frac{1}{4}\left(-\frac{1}{3}\right).

$$a=\frac{2}{3}$$

Whakakapia te \frac{2}{3} mō te a i te whārite b=2a-1.

$$b=2\times \frac{2}{3}-1$$

Tātaitia te b i te b=2\times \frac{2}{3}-1.

$$b=\frac{1}{3}$$

Kua oti te pūnaha te whakatau.

$$a=\frac{2}{3} b=\frac{1}{3} c=-\frac{1}{3}$$