Whakaoti i te {l}{0=4x+2B+C}{-3=-1x-1B+C}{0=4x-2B+C}

$$\left\{ \begin{array} { l } { 0 = 4 x + 2 B + C } \\ { - 3 = - 1 x - 1 B + C } \\ { 0 = 4 x - 2 B + C } \end{array} \right.$$

Whakaoti mō x, B, C

$$x=\frac{3}{5}=0.6$$

$$B=0$$

$$C = -\frac{12}{5} = -2\frac{2}{5} = -2.4$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me whakaoti te 0=4x+2B+C mō C.

$$C=-4x-2B$$

Whakakapia te -4x-2B mō te C i te whārite tuarua me te tuatoru.

$$-3=-x-B-4x-2B 0=4x-2B-4x-2B$$

Me whakaoti ēnei whārite mō x me B takitahi.

$$x=\frac{3}{5}-\frac{3}{5}B B=0$$

Whakakapia te 0 mō te B i te whārite x=\frac{3}{5}-\frac{3}{5}B.

$$x=\frac{3}{5}-\frac{3}{5}\times 0$$

Tātaitia te x i te x=\frac{3}{5}-\frac{3}{5}\times 0.

$$x=\frac{3}{5}$$

Whakakapia te \frac{3}{5} mō te x me te 0 mō B i te whārite C=-4x-2B.

$$C=-4\times \frac{3}{5}-2\times 0$$

Tātaitia te C i te C=-4\times \frac{3}{5}-2\times 0.

$$C=-\frac{12}{5}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{3}{5} B=0 C=-\frac{12}{5}$$