Whakaoti i te {l}{(4+B)1/2-B=3/4}{(2A+B)1/4-B=5/4}

$$\left\{ \begin{array} { l } { ( 4 + B ) \frac { 1 } { 2 } - B = \frac { 3 } { 4 } } \\ { ( 2 A + B ) \frac { 1 } { 4 } - B = \frac { 5 } { 4 } } \end{array} \right.$$

Whakaoti mō B, A

$$B = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

$$A = \frac{25}{4} = 6\frac{1}{4} = 6.25$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te 4+B ki te \frac{1}{2}.

$$2+\frac{1}{2}B-B=\frac{3}{4}$$

Pahekotia te \frac{1}{2}B me -B, ka -\frac{1}{2}B.

$$2-\frac{1}{2}B=\frac{3}{4}$$

Tangohia te 2 mai i ngā taha e rua.

$$-\frac{1}{2}B=\frac{3}{4}-2$$

Tangohia te 2 i te \frac{3}{4}, ka -\frac{5}{4}.

$$-\frac{1}{2}B=-\frac{5}{4}$$

Me whakarea ngā taha e rua ki te -2, te tau utu o -\frac{1}{2}.

$$B=-\frac{5}{4}\left(-2\right)$$

Whakareatia te -\frac{5}{4} ki te -2, ka \frac{5}{2}.

$$B=\frac{5}{2}$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$\left(2A+\frac{5}{2}\right)\times \frac{1}{4}-\frac{5}{2}=\frac{5}{4}$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2A+\frac{5}{2} ki te \frac{1}{4}.

$$\frac{1}{2}A+\frac{5}{8}-\frac{5}{2}=\frac{5}{4}$$

Tangohia te \frac{5}{2} i te \frac{5}{8}, ka -\frac{15}{8}.

$$\frac{1}{2}A-\frac{15}{8}=\frac{5}{4}$$

Me tāpiri te \frac{15}{8} ki ngā taha e rua.

$$\frac{1}{2}A=\frac{5}{4}+\frac{15}{8}$$

Tāpirihia te \frac{5}{4} ki te \frac{15}{8}, ka \frac{25}{8}.

$$\frac{1}{2}A=\frac{25}{8}$$

Me whakarea ngā taha e rua ki te 2, te tau utu o \frac{1}{2}.

$$A=\frac{25}{8}\times 2$$

Whakareatia te \frac{25}{8} ki te 2, ka \frac{25}{4}.

$$A=\frac{25}{4}$$

Kua oti te pūnaha te whakatau.

$$B=\frac{5}{2} A=\frac{25}{4}$$