Whakaoti i te ∫ (from 0 to 8) of (-133x)(-1/12x) wrt x

$$\int_{ 0 }^{ 8 } (-133x)(- \frac{ 1 }{ 12 } x) d x$$

Aromātai

$$\frac{17024}{9}\approx 1891.555555556$$

Ngā Upane Otinga

Whakareatia te x ki te x, ka x^{2}.

$$\int _{0}^{8}-133x^{2}\left(-\frac{1}{12}\right)\mathrm{d}x$$

Tuhia te -133\left(-\frac{1}{12}\right) hei hautanga kotahi.

$$\int _{0}^{8}\frac{-133\left(-1\right)}{12}x^{2}\mathrm{d}x$$

Whakareatia te -133 ki te -1, ka 133.

$$\int _{0}^{8}\frac{133}{12}x^{2}\mathrm{d}x$$

Aromātaitia te tau tōpū tautuhi-kore i te tuatahi.

$$\int \frac{133x^{2}}{12}\mathrm{d}x$$

Whakatauwehetia te pūmau mā te whakamahi i te \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.

$$\frac{133\int x^{2}\mathrm{d}x}{12}$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{2}\mathrm{d}x ki te \frac{x^{3}}{3}.

$$\frac{133x^{3}}{36}$$

Ko te tau tōpū tautuhi ko te pārōnaki kōaro o te kīanga i aromātaitia i te tepe tōrunga o te pāwhaitua, tangohia te pārōnaki kōaro i aromātaitia i te tepe tōraro o te pāwhaitua.

$$\frac{133}{36}\times 8^{3}-\frac{133}{36}\times 0^{3}$$

Whakarūnātia.

$$\frac{17024}{9}$$