Whakaoti i te ∫ (from 0 to 2) of (-3.6x+0.5x^2)(-0.1x) wrt x

$$\int_{ 0 }^{ 2 } (-3.6x+0.5 { x }^{ 2 } )(-0.1x) d x$$

Aromātai

$$0.76$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te -3.6x+0.5x^{2} ki te -0.1.

$$\int _{0}^{2}\left(0.36x-0.05x^{2}\right)x\mathrm{d}x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 0.36x-0.05x^{2} ki te x.

$$\int _{0}^{2}0.36x^{2}-0.05x^{3}\mathrm{d}x$$

Aromātaitia te tau tōpū tautuhi-kore i te tuatahi.

$$\int \frac{9x^{2}}{25}-\frac{x^{3}}{20}\mathrm{d}x$$

Kōmitimititia te kīanga tapeke mā te kīanga.

$$\int \frac{9x^{2}}{25}\mathrm{d}x+\int -\frac{x^{3}}{20}\mathrm{d}x$$

Whakatauwehea te pūmau i ēnei kīanga katoa.

$$\frac{9\int x^{2}\mathrm{d}x}{25}-\frac{\int x^{3}\mathrm{d}x}{20}$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{2}\mathrm{d}x ki te \frac{x^{3}}{3}. Whakareatia 0.36 ki te \frac{x^{3}}{3}.

$$\frac{3x^{3}}{25}-\frac{\int x^{3}\mathrm{d}x}{20}$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{3}\mathrm{d}x ki te \frac{x^{4}}{4}. Whakareatia -0.05 ki te \frac{x^{4}}{4}.

$$\frac{3x^{3}}{25}-\frac{x^{4}}{80}$$

Ko te tau tōpū tautuhi ko te pārōnaki kōaro o te kīanga i aromātaitia i te tepe tōrunga o te pāwhaitua, tangohia te pārōnaki kōaro i aromātaitia i te tepe tōraro o te pāwhaitua.

$$\frac{3}{25}\times 2^{3}-\frac{2^{4}}{80}-\left(\frac{3}{25}\times 0^{3}-\frac{0^{4}}{80}\right)$$

Whakarūnātia.

$$\frac{19}{25}$$