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Aromātai
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\int 1+\cos(x)\mathrm{d}x
Aromātaitia te tau tōpū tautuhi-kore i te tuatahi.
\int 1\mathrm{d}x+\int \cos(x)\mathrm{d}x
Kōmitimititia te kīanga tapeke mā te kīanga.
x+\int \cos(x)\mathrm{d}x
Kimihia te tau tōpū o 1 mā te whakamahi i te ture mō te ripanga o ngā tau tōpū pātahi \int a\mathrm{d}x=ax.
x+\sin(x)
Whakamahia te \int \cos(x)\mathrm{d}x=\sin(x) mai i te ripanga o ngā tau tōpū pātahi kia whakaputa i te huanga.
\frac{\pi }{2}+\sin(\frac{\pi }{2})-\left(-\frac{\pi }{2}+\sin(-\frac{\pi }{2})\right)
Ko te tau tōpū tautuhi ko te pārōnaki kōaro o te kīanga i aromātaitia i te tepe tōrunga o te pāwhaitua, tangohia te pārōnaki kōaro i aromātaitia i te tepe tōraro o te pāwhaitua.
\pi +2
Whakarūnātia.