Whakaoti i te ∫ esqrt{x wrt x=

$$\int{ e \sqrt{ x } }d x =$$

Aromātai

$$\frac{2ex^{\frac{3}{2}}}{3}+С$$

Ngā Upane Otinga

Whakatauwehetia te pūmau mā te whakamahi i te \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.

$$e\int \sqrt{x}\mathrm{d}x$$

Tuhia anō te \sqrt{x} hei x^{\frac{1}{2}}. Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{\frac{1}{2}}\mathrm{d}x ki te \frac{x^{\frac{3}{2}}}{\frac{3}{2}}. Whakarūnātia.

$$e\times \frac{2x^{\frac{3}{2}}}{3}$$

Whakarūnātia.

$$\frac{2ex^{\frac{3}{2}}}{3}$$

Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.

$$\frac{2ex^{\frac{3}{2}}}{3}+С$$

Kimi Pārōnaki e ai ki x

$$e\sqrt{x}$$