Aromātai
e^{x}+\frac{x^{2}}{4}+x+С
Kimi Pārōnaki e ai ki x
e^{x}+\frac{x}{2}+1
Tohaina
Kua tāruatia ki te papatopenga
\int e^{x}\mathrm{d}x+\int \frac{x}{2}\mathrm{d}x+\int 1\mathrm{d}x
Kōmitimititia te kīanga tapeke mā te kīanga.
\int e^{x}\mathrm{d}x+\frac{\int x\mathrm{d}x}{2}+\int 1\mathrm{d}x
Whakatauwehea te pūmau i ēnei kīanga katoa.
e^{x}+\frac{\int x\mathrm{d}x}{2}+\int 1\mathrm{d}x
Whakamahia te \int e^{x}\mathrm{d}x=e^{x} mai i te ripanga o ngā tau tōpū pātahi kia whakaputa i te huanga.
e^{x}+\frac{x^{2}}{4}+\int 1\mathrm{d}x
Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x\mathrm{d}x ki te \frac{x^{2}}{2}. Whakareatia \frac{1}{2} ki te \frac{x^{2}}{2}.
e^{x}+\frac{x^{2}}{4}+x
Kimihia te tau tōpū o 1 mā te whakamahi i te ture mō te ripanga o ngā tau tōpū pātahi \int a\mathrm{d}x=ax.
e^{x}+\frac{x^{2}}{4}+x+С
Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.
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