Aromātai
\frac{x^{4}}{12}+С
Kimi Pārōnaki e ai ki x
\frac{x^{3}}{3}
Tohaina
Kua tāruatia ki te papatopenga
\int \frac{x^{3}}{3}\mathrm{d}x
Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.
\frac{\int x^{3}\mathrm{d}x}{3}
Whakatauwehetia te pūmau mā te whakamahi i te \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.
\frac{x^{4}}{12}
Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{3}\mathrm{d}x ki te \frac{x^{4}}{4}.
\frac{x^{4}}{12}+С
Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.
Ngā Tauira
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