Whakaoti i te ∫ x^5+x^3-20x

$$\int x ^ { 5 } + x ^ { 3 } - 20 x$$

Aromātai

$$\frac{x^{6}}{6}+\frac{x^{4}}{4}-10x^{2}+С$$

Ngā Upane Otinga

Kōmitimititia te kīanga tapeke mā te kīanga.

$$\int x^{5}\mathrm{d}x+\int x^{3}\mathrm{d}x+\int -20x\mathrm{d}x$$

Whakatauwehea te pūmau i ēnei kīanga katoa.

$$\int x^{5}\mathrm{d}x+\int x^{3}\mathrm{d}x-20\int x\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{5}\mathrm{d}x ki te \frac{x^{6}}{6}.

$$\frac{x^{6}}{6}+\int x^{3}\mathrm{d}x-20\int x\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{3}\mathrm{d}x ki te \frac{x^{4}}{4}.

$$\frac{x^{6}}{6}+\frac{x^{4}}{4}-20\int x\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x\mathrm{d}x ki te \frac{x^{2}}{2}. Whakareatia -20 ki te \frac{x^{2}}{2}.

$$\frac{x^{6}}{6}+\frac{x^{4}}{4}-10x^{2}$$

Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.

$$\frac{x^{6}}{6}+\frac{x^{4}}{4}-10x^{2}+С$$

Kimi Pārōnaki e ai ki x

$$x\left(x^{4}+x^{2}-20\right)$$