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Aromātai
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Tohaina

\int \frac{1}{\sqrt{x}}\mathrm{d}x
Aromātaitia te tau tōpū tautuhi-kore i te tuatahi.
2\sqrt{x}
Tuhia anō te \frac{1}{\sqrt{x}} hei x^{-\frac{1}{2}}. Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{-\frac{1}{2}}\mathrm{d}x ki te \frac{x^{\frac{1}{2}}}{\frac{1}{2}}. Whakarūnāhia me te tahuri mai i te āhua taupū ki te āhua pūtake.
2\times 9^{\frac{1}{2}}-2\times 4^{\frac{1}{2}}
Ko te tau tōpū tautuhi ko te pārōnaki kōaro o te kīanga i aromātaitia i te tepe tōrunga o te pāwhaitua, tangohia te pārōnaki kōaro i aromātaitia i te tepe tōraro o te pāwhaitua.
2
Whakarūnātia.