Whakaoti i te ∫ (from 0 to 2) of (4x-x^3)^2 wrt x

$$\int _ { 0 } ^ { 2 } ( 4 x - x ^ { 3 } ) ^ { 2 } d x$$

Aromātai

$$\frac{1024}{105}\approx 9.752380952$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(4x-x^{3}\right)^{2}.

$$\int _{0}^{2}16x^{2}-8xx^{3}+\left(x^{3}\right)^{2}\mathrm{d}x$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 1 me te 3 kia riro ai te 4.

$$\int _{0}^{2}16x^{2}-8x^{4}+\left(x^{3}\right)^{2}\mathrm{d}x$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 3 me te 2 kia riro ai te 6.

$$\int _{0}^{2}16x^{2}-8x^{4}+x^{6}\mathrm{d}x$$

Aromātaitia te tau tōpū tautuhi-kore i te tuatahi.

$$\int 16x^{2}-8x^{4}+x^{6}\mathrm{d}x$$

Kōmitimititia te kīanga tapeke mā te kīanga.

$$\int 16x^{2}\mathrm{d}x+\int -8x^{4}\mathrm{d}x+\int x^{6}\mathrm{d}x$$

Whakatauwehea te pūmau i ēnei kīanga katoa.

$$16\int x^{2}\mathrm{d}x-8\int x^{4}\mathrm{d}x+\int x^{6}\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{2}\mathrm{d}x ki te \frac{x^{3}}{3}. Whakareatia 16 ki te \frac{x^{3}}{3}.

$$\frac{16x^{3}}{3}-8\int x^{4}\mathrm{d}x+\int x^{6}\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{4}\mathrm{d}x ki te \frac{x^{5}}{5}. Whakareatia -8 ki te \frac{x^{5}}{5}.

$$\frac{16x^{3}}{3}-\frac{8x^{5}}{5}+\int x^{6}\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{6}\mathrm{d}x ki te \frac{x^{7}}{7}.

$$\frac{16x^{3}}{3}-\frac{8x^{5}}{5}+\frac{x^{7}}{7}$$

Whakarūnātia.

$$\frac{x^{7}}{7}-\frac{8x^{5}}{5}+\frac{16x^{3}}{3}$$

Ko te tau tōpū tautuhi ko te pārōnaki kōaro o te kīanga i aromātaitia i te tepe tōrunga o te pāwhaitua, tangohia te pārōnaki kōaro i aromātaitia i te tepe tōraro o te pāwhaitua.

$$\frac{2^{7}}{7}-\frac{8}{5}\times 2^{5}+\frac{16}{3}\times 2^{3}-\left(\frac{0^{7}}{7}-\frac{8}{5}\times 0^{5}+\frac{16}{3}\times 0^{3}\right)$$

Whakarūnātia.

$$\frac{1024}{105}$$