Whakaoti i te ∫ (from 0 to 1) of x^2(1-x)^3

$$\int _ { 0 } ^ { 1 } x ^ { 2 } ( 1 - x ) ^ { 3 }$$

Aromātai

$$\frac{1}{60}\approx 0.016666667$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} hei whakaroha \left(1-x\right)^{3}.

$$\int _{0}^{1}x^{2}\left(1-3x+3x^{2}-x^{3}\right)\mathrm{d}x$$

Whakamahia te āhuatanga tohatoha hei whakarea te x^{2} ki te 1-3x+3x^{2}-x^{3}.

$$\int _{0}^{1}x^{2}-3x^{3}+3x^{4}-x^{5}\mathrm{d}x$$

Aromātaitia te tau tōpū tautuhi-kore i te tuatahi.

$$\int x^{2}-3x^{3}+3x^{4}-x^{5}\mathrm{d}x$$

Kōmitimititia te kīanga tapeke mā te kīanga.

$$\int x^{2}\mathrm{d}x+\int -3x^{3}\mathrm{d}x+\int 3x^{4}\mathrm{d}x+\int -x^{5}\mathrm{d}x$$

Whakatauwehea te pūmau i ēnei kīanga katoa.

$$\int x^{2}\mathrm{d}x-3\int x^{3}\mathrm{d}x+3\int x^{4}\mathrm{d}x-\int x^{5}\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{2}\mathrm{d}x ki te \frac{x^{3}}{3}.

$$\frac{x^{3}}{3}-3\int x^{3}\mathrm{d}x+3\int x^{4}\mathrm{d}x-\int x^{5}\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{3}\mathrm{d}x ki te \frac{x^{4}}{4}. Whakareatia -3 ki te \frac{x^{4}}{4}.

$$\frac{x^{3}}{3}-\frac{3x^{4}}{4}+3\int x^{4}\mathrm{d}x-\int x^{5}\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{4}\mathrm{d}x ki te \frac{x^{5}}{5}. Whakareatia 3 ki te \frac{x^{5}}{5}.

$$\frac{x^{3}}{3}-\frac{3x^{4}}{4}+\frac{3x^{5}}{5}-\int x^{5}\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{5}\mathrm{d}x ki te \frac{x^{6}}{6}. Whakareatia -1 ki te \frac{x^{6}}{6}.

$$\frac{x^{3}}{3}-\frac{3x^{4}}{4}+\frac{3x^{5}}{5}-\frac{x^{6}}{6}$$

Whakarūnātia.

$$-\frac{x^{6}}{6}+\frac{3x^{5}}{5}-\frac{3x^{4}}{4}+\frac{x^{3}}{3}$$

Ko te tau tōpū tautuhi ko te pārōnaki kōaro o te kīanga i aromātaitia i te tepe tōrunga o te pāwhaitua, tangohia te pārōnaki kōaro i aromātaitia i te tepe tōraro o te pāwhaitua.

$$-\frac{1^{6}}{6}+\frac{3}{5}\times 1^{5}-\frac{3}{4}\times 1^{4}+\frac{1^{3}}{3}-\left(-\frac{0^{6}}{6}+\frac{3}{5}\times 0^{5}-\frac{3}{4}\times 0^{4}+\frac{0^{3}}{3}\right)$$

Whakarūnātia.

$$\frac{1}{60}$$