Whakaoti i te ∫ (from 0 to 1) of 1/2v^2dv

$$\int _ { 0 } ^ { 1 } \frac { 1 } { 2 } v ^ { 2 } d v$$

Aromātai

$$\frac{1}{6}\approx 0.166666667$$

Ngā Upane Otinga

Aromātaitia te tau tōpū tautuhi-kore i te tuatahi.

$$\int \frac{v^{2}}{2}\mathrm{d}v$$

Whakatauwehetia te pūmau mā te whakamahi i te \int af\left(v\right)\mathrm{d}v=a\int f\left(v\right)\mathrm{d}v.

$$\frac{\int v^{2}\mathrm{d}v}{2}$$

Nā te mea \int v^{k}\mathrm{d}v=\frac{v^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int v^{2}\mathrm{d}v ki te \frac{v^{3}}{3}.

$$\frac{v^{3}}{6}$$

Ko te tau tōpū tautuhi ko te pārōnaki kōaro o te kīanga i aromātaitia i te tepe tōrunga o te pāwhaitua, tangohia te pārōnaki kōaro i aromātaitia i te tepe tōraro o te pāwhaitua.

$$\frac{1^{3}}{6}-\frac{0^{3}}{6}$$

Whakarūnātia.

$$\frac{1}{6}$$