Whakaoti i te ∫ (from 0 to 05) of (528x+384x^2) wrt x=

$$\int _ { 0 } ^ { 05 } ( 528 x + 384 x ^ { 2 } ) d x =$$

Aromātai

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Ngā Upane Otinga

Aromātaitia te tau tōpū tautuhi-kore i te tuatahi.

$$\int 528x+384x^{2}\mathrm{d}x$$

Kōmitimititia te kīanga tapeke mā te kīanga.

$$\int 528x\mathrm{d}x+\int 384x^{2}\mathrm{d}x$$

Whakatauwehea te pūmau i ēnei kīanga katoa.

$$528\int x\mathrm{d}x+384\int x^{2}\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x\mathrm{d}x ki te \frac{x^{2}}{2}. Whakareatia 528 ki te \frac{x^{2}}{2}.

$$264x^{2}+384\int x^{2}\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{2}\mathrm{d}x ki te \frac{x^{3}}{3}. Whakareatia 384 ki te \frac{x^{3}}{3}.

$$264x^{2}+128x^{3}$$

Ko te tau tōpū tautuhi ko te pārōnaki kōaro o te kīanga i aromātaitia i te tepe tōrunga o te pāwhaitua, tangohia te pārōnaki kōaro i aromātaitia i te tepe tōraro o te pāwhaitua.

$$264\times \left(0\times 5\right)^{2}+128\times \left(0\times 5\right)^{3}-\left(264\times 0^{2}+128\times 0^{3}\right)$$

Whakarūnātia.

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