Whakaoti i te ∫ (from 0 to pi / 3) of (1-cosθ)^2

$$\int _ { 0 } ^ { \pi / 3 } ( 1 - \cos \theta ) ^ { 2 }$$

Aromātai

$$\frac{\pi \left(\cos(\theta )-1\right)^{2}}{3}$$

Ngā Upane Otinga

Aromātaitia te tau tōpū tautuhi-kore i te tuatahi.

$$\int \left(1-\cos(\theta )\right)^{2}\mathrm{d}x$$

Kimihia te tau tōpū o \left(1-\cos(\theta )\right)^{2} mā te whakamahi i te ture mō te ripanga o ngā tau tōpū pātahi \int a\mathrm{d}x=ax.

$$\left(1-\cos(\theta )\right)^{2}x$$

Ko te tau tōpū tautuhi ko te pārōnaki kōaro o te kīanga i aromātaitia i te tepe tōrunga o te pāwhaitua, tangohia te pārōnaki kōaro i aromātaitia i te tepe tōraro o te pāwhaitua.

$$\frac{1}{3}\left(1-\cos(\theta )\right)^{2}\pi +0\left(1-\cos(\theta )\right)^{2}$$

Whakarūnātia.

$$\frac{\left(\cos(\theta )-1\right)^{2}\pi }{3}$$

Kimi Pārōnaki e ai ki θ

$$-\frac{2\pi \sin(\theta )\left(\cos(\theta )-1\right)}{3}$$