Whakaoti i te ∫ (from - 1 to 1) of 2x^2+4 wrt x

$$\int _ { - 1 } ^ { 1 } 2 x ^ { 2 } + 4 d x$$

Aromātai

$$\frac{28}{3}\approx 9.333333333$$

Ngā Upane Otinga

Aromātaitia te tau tōpū tautuhi-kore i te tuatahi.

$$\int 2x^{2}+4\mathrm{d}x$$

Kōmitimititia te kīanga tapeke mā te kīanga.

$$\int 2x^{2}\mathrm{d}x+\int 4\mathrm{d}x$$

Whakatauwehea te pūmau i ēnei kīanga katoa.

$$2\int x^{2}\mathrm{d}x+\int 4\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{2}\mathrm{d}x ki te \frac{x^{3}}{3}. Whakareatia 2 ki te \frac{x^{3}}{3}.

$$\frac{2x^{3}}{3}+\int 4\mathrm{d}x$$

Kimihia te tau tōpū o 4 mā te whakamahi i te ture mō te ripanga o ngā tau tōpū pātahi \int a\mathrm{d}x=ax.

$$\frac{2x^{3}}{3}+4x$$

Ko te tau tōpū tautuhi ko te pārōnaki kōaro o te kīanga i aromātaitia i te tepe tōrunga o te pāwhaitua, tangohia te pārōnaki kōaro i aromātaitia i te tepe tōraro o te pāwhaitua.

$$\frac{2}{3}\times 1^{3}+4\times 1-\left(\frac{2}{3}\left(-1\right)^{3}+4\left(-1\right)\right)$$

Whakarūnātia.

$$\frac{28}{3}$$