Aromātai
\frac{3x^{4}}{4}+\frac{9x^{2}}{2}+С
Kimi Pārōnaki e ai ki x
3x\left(x^{2}+3\right)
Tohaina
Kua tāruatia ki te papatopenga
\int 3x^{3}+9x\mathrm{d}x
Whakamahia te āhuatanga tohatoha hei whakarea te 3x ki te x^{2}+3.
\int 3x^{3}\mathrm{d}x+\int 9x\mathrm{d}x
Kōmitimititia te kīanga tapeke mā te kīanga.
3\int x^{3}\mathrm{d}x+9\int x\mathrm{d}x
Whakatauwehea te pūmau i ēnei kīanga katoa.
\frac{3x^{4}}{4}+9\int x\mathrm{d}x
Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{3}\mathrm{d}x ki te \frac{x^{4}}{4}. Whakareatia 3 ki te \frac{x^{4}}{4}.
\frac{3x^{4}}{4}+\frac{9x^{2}}{2}
Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x\mathrm{d}x ki te \frac{x^{2}}{2}. Whakareatia 9 ki te \frac{x^{2}}{2}.
\frac{3x^{4}}{4}+\frac{9x^{2}}{2}+С
Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.
Ngā Tauira
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