Whakaoti i te ∫ (3x+2)^3

$$\int ( 3 x + 2 ) ^ { 3 }$$

Aromātai

$$\frac{\left(3x+2\right)^{4}}{12}+С$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} hei whakaroha \left(3x+2\right)^{3}.

$$\int 27x^{3}+54x^{2}+36x+8\mathrm{d}x$$

Kōmitimititia te kīanga tapeke mā te kīanga.

$$\int 27x^{3}\mathrm{d}x+\int 54x^{2}\mathrm{d}x+\int 36x\mathrm{d}x+\int 8\mathrm{d}x$$

Whakatauwehea te pūmau i ēnei kīanga katoa.

$$27\int x^{3}\mathrm{d}x+54\int x^{2}\mathrm{d}x+36\int x\mathrm{d}x+\int 8\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{3}\mathrm{d}x ki te \frac{x^{4}}{4}. Whakareatia 27 ki te \frac{x^{4}}{4}.

$$\frac{27x^{4}}{4}+54\int x^{2}\mathrm{d}x+36\int x\mathrm{d}x+\int 8\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{2}\mathrm{d}x ki te \frac{x^{3}}{3}. Whakareatia 54 ki te \frac{x^{3}}{3}.

$$\frac{27x^{4}}{4}+18x^{3}+36\int x\mathrm{d}x+\int 8\mathrm{d}x$$

Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x\mathrm{d}x ki te \frac{x^{2}}{2}. Whakareatia 36 ki te \frac{x^{2}}{2}.

$$\frac{27x^{4}}{4}+18x^{3}+18x^{2}+\int 8\mathrm{d}x$$

Kimihia te tau tōpū o 8 mā te whakamahi i te ture mō te ripanga o ngā tau tōpū pātahi \int a\mathrm{d}x=ax.

$$\frac{27x^{4}}{4}+18x^{3}+18x^{2}+8x$$

Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.

$$\frac{27x^{4}}{4}+18x^{3}+18x^{2}+8x+С$$

Kimi Pārōnaki e ai ki x

$$\left(3x+2\right)^{3}$$