Aromātai
\frac{2x^{5}}{5}+x+С
Kimi Pārōnaki e ai ki x
2x^{4}+1
Tohaina
Kua tāruatia ki te papatopenga
\int 1\mathrm{d}x+\int 2x^{4}\mathrm{d}x
Kōmitimititia te kīanga tapeke mā te kīanga.
\int 1\mathrm{d}x+2\int x^{4}\mathrm{d}x
Whakatauwehea te pūmau i ēnei kīanga katoa.
x+2\int x^{4}\mathrm{d}x
Kimihia te tau tōpū o 1 mā te whakamahi i te ture mō te ripanga o ngā tau tōpū pātahi \int a\mathrm{d}x=ax.
x+\frac{2x^{5}}{5}
Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{4}\mathrm{d}x ki te \frac{x^{5}}{5}. Whakareatia 2 ki te \frac{x^{5}}{5}.
x+\frac{2x^{5}}{5}+С
Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.
Ngā Tauira
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