Whakaoti i te ∫ sqrt{L^2-k^2}

$$\int \sqrt { L ^ { 2 } - k ^ { 2 } }$$

Aromātai

$$x\sqrt{L^{2}-k^{2}}+С$$

$$|L|\geq |k|$$

Ngā Upane Otinga

Kimihia te tau tōpū o \sqrt{L^{2}-k^{2}} mā te whakamahi i te ture mō te ripanga o ngā tau tōpū pātahi \int a\mathrm{d}x=ax.

$$\sqrt{L^{2}-k^{2}}x$$

Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.

$$\begin{matrix}\sqrt{L^{2}-k^{2}}x+С_{3},&\end{matrix}$$

Kimi Pārōnaki e ai ki x

$$\sqrt{L^{2}-k^{2}}$$