Aromātai
\frac{2\sqrt{6}x^{\frac{3}{2}}}{3}+С
Kimi Pārōnaki e ai ki x
\sqrt{6x}
Tohaina
Kua tāruatia ki te papatopenga
\sqrt{6}\int \sqrt{x}\mathrm{d}x
Whakatauwehetia te pūmau mā te whakamahi i te \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.
\sqrt{6}\times \frac{2x^{\frac{3}{2}}}{3}
Tuhia anō te \sqrt{x} hei x^{\frac{1}{2}}. Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{\frac{1}{2}}\mathrm{d}x ki te \frac{x^{\frac{3}{2}}}{\frac{3}{2}}. Whakarūnātia.
\frac{2\sqrt{6}x^{\frac{3}{2}}}{3}
Whakarūnātia.
\frac{2\sqrt{6}x^{\frac{3}{2}}}{3}+С
Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.
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