Whakaoti i te ∫ wrt x/sqrt[3]{x}=3x^2/3/2+c

$$\int \frac { d x } { \sqrt[ 3 ] { x } } = \frac { 3 x ^ { 2 / 3 } } { 2 } + c$$

Whakaoti mō c

$$c=С$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 2.

$$2\int \frac{1}{\sqrt[3]{x}}\mathrm{d}x=3x^{\frac{2}{3}}+2c$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$3x^{\frac{2}{3}}+2c=2\int \frac{1}{\sqrt[3]{x}}\mathrm{d}x$$

Tangohia te 3x^{\frac{2}{3}} mai i ngā taha e rua.

$$2c=2\int \frac{1}{\sqrt[3]{x}}\mathrm{d}x-3x^{\frac{2}{3}}$$

He hanga arowhānui tō te whārite.

$$2c=2С+\frac{2x}{\sqrt[3]{x}}-3x^{\frac{2}{3}}$$

Whakawehea ngā taha e rua ki te 2.

$$\frac{2c}{2}=\frac{2С-x^{\frac{2}{3}}}{2}$$

Mā te whakawehe ki te 2 ka wetekia te whakareanga ki te 2.

$$c=\frac{2С-x^{\frac{2}{3}}}{2}$$

Whakawehe 2С-x^{\frac{2}{3}} ki te 2.

$$c=-\frac{x^{\frac{2}{3}}}{2}+С$$

Whakaoti mō x

$$x\neq 0$$

$$c=С\text{ and }x\neq 0$$