Whakaoti i te ∫ wrt x/sqrt[3]{8x^2}

$$\int \frac { d x } { \sqrt[ 3 ] { 8 x ^ { 2 } } }$$

Aromātai

$$\frac{3\sqrt[3]{x}}{2}+С$$

Ngā Upane Otinga

Whakatauwehetia te pūmau mā te whakamahi i te \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.

$$\frac{\int \frac{1}{\sqrt[3]{x^{2}}}\mathrm{d}x}{\sqrt[3]{8}}$$

Tuhia anō te \frac{1}{x^{\frac{2}{3}}} hei x^{-\frac{2}{3}}. Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{-\frac{2}{3}}\mathrm{d}x ki te \frac{x^{\frac{1}{3}}}{\frac{1}{3}}. Whakarūnāhia me te tahuri mai i te āhua taupū ki te āhua pūtake.

$$\frac{3\sqrt[3]{x}}{\sqrt[3]{8}}$$

Whakarūnātia.

$$\frac{3\sqrt[3]{x}}{2}$$

Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.

$$\frac{3\sqrt[3]{x}}{2}+С$$

Kimi Pārōnaki e ai ki x

$$\frac{1}{2x^{\frac{2}{3}}}$$