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Tohaina

\frac{u}{\sqrt{25x^{2}-9}}
Kimihia te tau tōpū o \frac{1}{\sqrt{25x^{2}-9}} mā te whakamahi i te ture mō te ripanga o ngā tau tōpū pātahi \int a\mathrm{d}u=au.
\frac{u}{\sqrt{25x^{2}-9}}+С
Mēnā ko F\left(u\right) he pārōnaki kōaro o f\left(u\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(u\right) ka whakaaturia e F\left(u\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.