Whakaoti i te ∫ 6 wrt x/sqrt[3]{x}

$$\int \frac { 6 d x } { \sqrt[ 3 ] { x } }$$

Aromātai

$$9x^{\frac{2}{3}}+С$$

Ngā Upane Otinga

Whakatauwehetia te pūmau mā te whakamahi i te \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.

$$6\int \frac{1}{\sqrt[3]{x}}\mathrm{d}x$$

Tuhia anō te \frac{1}{\sqrt[3]{x}} hei x^{-\frac{1}{3}}. Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x^{-\frac{1}{3}}\mathrm{d}x ki te \frac{x^{\frac{2}{3}}}{\frac{2}{3}}. Whakarūnātia. Whakareatia 6 ki te \frac{3x^{\frac{2}{3}}}{2}.

$$9x^{\frac{2}{3}}$$

Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.

$$9x^{\frac{2}{3}}+С$$

Kimi Pārōnaki e ai ki x

$$\frac{6}{\sqrt[3]{x}}$$