Whakaoti i te ∫ 2k/3-5y/4=-3

$$\int \frac { 2 k } { 3 } - \frac { 5 y } { 4 } = - 3$$

Whakaoti mō y

$$y=\frac{8kx+С}{15}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 4.

$$4\int \frac{2k}{3}\mathrm{d}x-5y=-12$$

Tangohia te 4\int \frac{2k}{3}\mathrm{d}x mai i ngā taha e rua.

$$-5y=-12-4\int \frac{2k}{3}\mathrm{d}x$$

He hanga arowhānui tō te whārite.

$$-5y=-\frac{8kx}{3}-4С-12$$

Whakawehea ngā taha e rua ki te -5.

$$\frac{-5y}{-5}=\frac{-\frac{8kx}{3}-4С-12}{-5}$$

Mā te whakawehe ki te -5 ka wetekia te whakareanga ki te -5.

$$y=\frac{-\frac{8kx}{3}-4С-12}{-5}$$

Whakawehe -12-\frac{8kx}{3}-4С ki te -5.

$$y=\frac{8kx}{15}+\frac{4С}{5}+\frac{12}{5}$$

Whakaoti mō k

$$\left\{\begin{matrix}k=\frac{15y-С}{8x}\text{, }&x\neq 0\\k\in \mathrm{R}\text{, }&y=\frac{4С}{5}\text{ and }x=0\end{matrix}\right.$$