Whakaoti i te ∫ 2dt/t^2=2/t+c

$$\int \frac { 2 d t } { t ^ { 2 } } = \frac { 2 } { t } + c$$

Whakaoti mō c

$$c=-\frac{4}{t}+С$$

$$t\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te t.

$$t\int \frac{2}{t^{2}}\mathrm{d}t=2+tc$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$2+tc=t\int \frac{2}{t^{2}}\mathrm{d}t$$

Tangohia te 2 mai i ngā taha e rua.

$$tc=t\int \frac{2}{t^{2}}\mathrm{d}t-2$$

He hanga arowhānui tō te whārite.

$$tc=Сt-4$$

Whakawehea ngā taha e rua ki te t.

$$\frac{tc}{t}=\frac{Сt-4}{t}$$

Mā te whakawehe ki te t ka wetekia te whakareanga ki te t.

$$c=\frac{Сt-4}{t}$$

Whakawehe -4+Сt ki te t.

$$c=-\frac{4}{t}+С$$

Whakaoti mō t

$$t=\frac{4}{С-c}$$

$$c\neq С$$