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Kimi Pārōnaki e ai ki x
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Tohaina

-\frac{1}{2x^{2}}
Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int \frac{1}{x^{3}}\mathrm{d}x ki te -\frac{1}{2x^{2}}.
-\frac{1}{2x^{2}}+С
Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.