Whakaoti i te ∫ -3x^-05/-6x^05+18 wrt x=?

$$\int \frac { - 3 x ^ { - 05 } } { - 6 x ^ { 05 } + 18 } d x = ?$$

Aromātai

$$-\frac{x}{4}+С$$

Ngā Upane Otinga

Whakareatia te 0 ki te 5, ka 0.

$$\int \frac{-3x^{0}}{-6x^{0\times 5}+18}\mathrm{d}x$$

Tātaihia te x mā te pū o 0, kia riro ko 1.

$$\int \frac{-3}{-6x^{0\times 5}+18}\mathrm{d}x$$

Whakareatia te 0 ki te 5, ka 0.

$$\int \frac{-3}{-6x^{0}+18}\mathrm{d}x$$

Tātaihia te x mā te pū o 0, kia riro ko 1.

$$\int \frac{-3}{-6+18}\mathrm{d}x$$

Tāpirihia te -6 ki te 18, ka 12.

$$\int \frac{-3}{12}\mathrm{d}x$$

Whakahekea te hautanga \frac{-3}{12} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$\int -\frac{1}{4}\mathrm{d}x$$

Kimihia te tau tōpū o -\frac{1}{4} mā te whakamahi i te ture mō te ripanga o ngā tau tōpū pātahi \int a\mathrm{d}x=ax.

$$-\frac{x}{4}$$

Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.

$$-\frac{x}{4}+С$$

Kimi Pārōnaki e ai ki x

$$-\frac{1}{4} = -0.25$$