Aromātai
\frac{x^{2}}{2}+С
Kimi Pārōnaki e ai ki x
x
Tohaina
Kua tāruatia ki te papatopenga
\int x^{1}\mathrm{d}x
Hei whakawehe ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga. Me tango te 1 i te 2 kia riro ai te 1.
\int x\mathrm{d}x
Tātaihia te x mā te pū o 1, kia riro ko x.
\frac{x^{2}}{2}
Nā te mea \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} mō te k\neq -1, me whakakapi \int x\mathrm{d}x ki te \frac{x^{2}}{2}.
\frac{x^{2}}{2}+С
Mēnā ko F\left(x\right) he pārōnaki kōaro o f\left(x\right), kāti ko te huinga o ngā pārōnaki kōaro katoa o f\left(x\right) ka whakaaturia e F\left(x\right)+C. Nō reira, me tāpiri te pūmau o te whakatōpūtanga C\in \mathrm{R} ki te otinga.
Ngā Tauira
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Poukapa
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Whakarerekētanga
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Ngā Tepe
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