Whakaoti mō γ_1
\gamma _{1}=v^{2}+5
Whakaoti mō v (complex solution)
v=-\sqrt{\gamma _{1}-5}
v=\sqrt{\gamma _{1}-5}
Whakaoti mō v
v=\sqrt{\gamma _{1}-5}
v=-\sqrt{\gamma _{1}-5}\text{, }\gamma _{1}\geq 5
Tohaina
Kua tāruatia ki te papatopenga
\gamma _{1}=5+v^{2}
Me tāpiri te v^{2} ki ngā taha e rua.
Ngā Tauira
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{ x } ^ { 2 } - 4 x - 5 = 0
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