Whakaoti i te d/dxleft(1/x(x-y)right)

$$\frac{d}{d x } \left( \frac{ 1 }{ x(x-y) } \right)$$

Aromātai

$$\frac{y-2x}{\left(x\left(x-y\right)\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x-y.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{1}{x^{2}-xy})$$

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\left(x^{2}+\left(-y\right)x^{1}\right)^{-1-1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}+\left(-y\right)x^{1})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\left(x^{2}+\left(-y\right)x^{1}\right)^{-2}\left(2x^{2-1}+\left(-y\right)x^{1-1}\right)$$

Whakarūnātia.

$$\left(x^{2}+\left(-y\right)x^{1}\right)^{-2}\left(-2x^{1}+yx^{0}\right)$$

Mō tētahi kupu t, t^{1}=t.

$$\left(x^{2}+\left(-y\right)x\right)^{-2}\left(-2x+yx^{0}\right)$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\left(x^{2}+\left(-y\right)x\right)^{-2}\left(-2x+y\times 1\right)$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\left(x^{2}+\left(-y\right)x\right)^{-2}\left(-2x+y\right)$$

Kimi Pārōnaki e ai ki x

$$\frac{2\left(3x^{2}-3xy+y^{2}\right)}{\left(x\left(x-y\right)\right)^{3}}$$