Whakaoti i te d/dxleft(x^3+1/x^2-x-2right)

$$\frac{d}{d x } \left( \frac{ { x }^{ 3 } +1 }{ { x }^{ 2 } -x-2 } \right)$$

Aromātai

$$\frac{x^{2}-4x+1}{\left(x-2\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{2}-x^{1}-2\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{3}+1)-\left(x^{3}+1\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}-x^{1}-2)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{2}-x^{1}-2\right)\times 3x^{3-1}-\left(x^{3}+1\right)\left(2x^{2-1}-x^{1-1}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Whakarūnātia.

$$\frac{\left(x^{2}-x^{1}-2\right)\times 3x^{2}-\left(x^{3}+1\right)\left(2x^{1}-x^{0}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Whakareatia x^{2}-x^{1}-2 ki te 3x^{2}.

$$\frac{x^{2}\times 3x^{2}-x^{1}\times 3x^{2}-2\times 3x^{2}-\left(x^{3}+1\right)\left(2x^{1}-x^{0}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Whakareatia x^{3}+1 ki te 2x^{1}-x^{0}.

$$\frac{x^{2}\times 3x^{2}-x^{1}\times 3x^{2}-2\times 3x^{2}-\left(x^{3}\times 2x^{1}+x^{3}\left(-1\right)x^{0}+2x^{1}-x^{0}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{3x^{2+2}-3x^{1+2}-2\times 3x^{2}-\left(2x^{3+1}-x^{3}+2x^{1}-x^{0}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Whakarūnātia.

$$\frac{3x^{4}-3x^{3}-6x^{2}-\left(2x^{4}-x^{3}+2x^{1}-x^{0}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{x^{4}-2x^{3}-6x^{2}-2x^{1}-\left(-x^{0}\right)}{\left(x^{2}-x^{1}-2\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{x^{4}-2x^{3}-6x^{2}-2x-\left(-x^{0}\right)}{\left(x^{2}-x-2\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{x^{4}-2x^{3}-6x^{2}-2x-\left(-1\right)}{\left(x^{2}-x-2\right)^{2}}$$

Kimi Pārōnaki e ai ki x

$$\frac{6}{\left(x-2\right)^{3}}$$