Whakaoti i te d/dxleft(x^2+7/x-5right)

$$\frac{d}{d x } \left( \frac{ { x }^{ 2 } +7 }{ x-5 } \right)$$

Aromātai

$$\frac{x^{2}-10x-7}{\left(x-5\right)^{2}}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Otinga

Mō ngā pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te otinga o ngā pānga e rua ko te tauraro whakareatia ki te pārōnaki o te taurunga tango i te taurunga whakareatia ki te pārōnaki o te tauraro, ā, ka whakawehea te katoa ki te tauraro kua pūruatia.

$$\frac{\left(x^{1}-5\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{2}+7)-\left(x^{2}+7\right)\frac{\mathrm{d}}{\mathrm{d}x}(x^{1}-5)}{\left(x^{1}-5\right)^{2}}$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{\left(x^{1}-5\right)\times 2x^{2-1}-\left(x^{2}+7\right)x^{1-1}}{\left(x^{1}-5\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{\left(x^{1}-5\right)\times 2x^{1}-\left(x^{2}+7\right)x^{0}}{\left(x^{1}-5\right)^{2}}$$

Whakarohaina mā te āhuatanga tohatoha.

$$\frac{x^{1}\times 2x^{1}-5\times 2x^{1}-\left(x^{2}x^{0}+7x^{0}\right)}{\left(x^{1}-5\right)^{2}}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{2x^{1+1}-5\times 2x^{1}-\left(x^{2}+7x^{0}\right)}{\left(x^{1}-5\right)^{2}}$$

Mahia ngā tātaitanga.

$$\frac{2x^{2}-10x^{1}-\left(x^{2}+7x^{0}\right)}{\left(x^{1}-5\right)^{2}}$$

Tangohia ngā taiapa kāore i te hiahiatia.

$$\frac{2x^{2}-10x^{1}-x^{2}-7x^{0}}{\left(x^{1}-5\right)^{2}}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{\left(2-1\right)x^{2}-10x^{1}-7x^{0}}{\left(x^{1}-5\right)^{2}}$$

Tango 1 mai i 2.

$$\frac{x^{2}-10x^{1}-7x^{0}}{\left(x^{1}-5\right)^{2}}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{x^{2}-10x-7x^{0}}{\left(x-5\right)^{2}}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{x^{2}-10x-7\times 1}{\left(x-5\right)^{2}}$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{x^{2}-10x-7}{\left(x-5\right)^{2}}$$

Kimi Pārōnaki e ai ki x

$$\frac{64}{\left(x-5\right)^{3}}$$