Whakaoti i te x+4/x=x/x+4

$$\frac{ x+4 }{ x } = \frac{ x }{ x+4 }$$

Whakaoti mō x

$$x=-2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tē taea kia ōrite te tāupe x ki tētahi o ngā uara -4,0 nā te kore tautuhi i te whakawehenga mā te kore. Me whakarea ngā taha e rua o te whārite ki te x\left(x+4\right), arā, te tauraro pātahi he tino iti rawa te kitea o x,x+4.

$$\left(x+4\right)\left(x+4\right)=xx$$

Whakareatia te x+4 ki te x+4, ka \left(x+4\right)^{2}.

$$\left(x+4\right)^{2}=xx$$

Whakareatia te x ki te x, ka x^{2}.

$$\left(x+4\right)^{2}=x^{2}$$

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(x+4\right)^{2}.

$$x^{2}+8x+16=x^{2}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$x^{2}+8x+16-x^{2}=0$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$8x+16=0$$

Tangohia te 16 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$8x=-16$$

Whakawehea ngā taha e rua ki te 8.

$$x=\frac{-16}{8}$$

Whakawehea te -16 ki te 8, kia riro ko -2.

$$x=-2$$